From: mame@... Date: 2020-01-12T23:44:36+00:00 Subject: [ruby-core:96820] [Ruby master Bug#16504] `foo(*args, &args.pop)` should pass all elements of args Issue #16504 has been updated by mame (Yusuke Endoh). Okay, I'll ask matz which is right. But I believe that the 2.6 and current behavior is wrong because Ruby has a principle of left-to-right evaluation. Actually, `foo(*ary, ary.pop)` was changed between 2.1 and 2.2; 2.2 and later duplicate the last argument. And what do you think about `foo(*ary, 42, &ary.pop)`? ---------------------------------------- Bug #16504: `foo(*args, &args.pop)` should pass all elements of args https://bugs.ruby-lang.org/issues/16504#change-83814 * Author: mame (Yusuke Endoh) * Status: Open * Priority: Normal * Assignee: * Target version: * ruby -v: ruby 2.7.0p0 (2019-12-25 revision 647ee6f091) [x86_64-linux] * Backport: 2.5: UNKNOWN, 2.6: UNKNOWN, 2.7: UNKNOWN ---------------------------------------- https://bugs.ruby-lang.org/issues/16500?next_issue_id=16499&prev_issue_id=16501#note-7 ``` # in 2.7 args = [1, 2, -> {}]; foo( *args, &args.pop) #=> passes [1, 2] (bug; [1, 2, ->{}] is expected) args = [1, 2, -> {}]; foo(0, *args, &args.pop) #=> passes [0, 1, 2, ->{}] (good) ``` -- https://bugs.ruby-lang.org/ Unsubscribe: