From: ts <decoux@...>
Date: 2000-10-22T20:50:41+09:00
Subject: [ruby-talk:5752] Re: Some newbye question

>>>>> "G" == Guy N Hurst <gnhurst@hurstlinks.com> writes:

 I see 2 problems with your idea

G>  		block{|a~,b~| 

 if someone has defined a def 'block', it will have a problem no ?

G> 			b # block variable, has value 12
G> 			a # block variable, has value 24

 You can't move the block with cut/paste because the value of 'a', and 'b'
depend of the previous variable 'a' and 'b', no ?

G> 			b = 24
G> 			a = 36 

G> Could this be implemented?

 You can perhaps implement a 'let' if you re-use an existing keyword like
 for example 'do'

 Something like this :

pigeon% cat b.rb
#!./ruby
def toto(a)
   p "1 #{a}"
   do(a = 24, b = 2)
      p "2 #{a}, #{b}"
      do a = a + 2, b = a + 10
         p "3 #{a}, #{b}"
      end
      p "4 #{a}, #{b}"
   end
   p "5 #{a}"
end
toto(12)
pigeon% 

pigeon% b.rb
"1 12"
"2 24, 2"
"3 26, 34"
"4 24, 2"
"5 12"
pigeon% 

 You have no incompatibilities, because you can't write actually
 'do(a) ... end'

 Unfortunately :
  * now you have 3 'do' :-(
  * you need 2 new nodes



Guy Decoux