[#6363] Re: rescue clause affecting IO loop behavior — ts <decoux@...>

>>>>> "D" == David Alan Black <dblack@candle.superlink.net> writes:

17 messages 2000/11/14
[#6367] Re: rescue clause affecting IO loop behavior — David Alan Black <dblack@...> 2000/11/14

Hello again --

[#6582] best way to interleaf arrays? — David Alan Black <dblack@...>

Hello --

15 messages 2000/11/26

[#6646] RE: Array Intersect (&) question — Aleksi Niemel<aleksi.niemela@...>

Ross asked something about widely known and largely ignored language (on

23 messages 2000/11/29
[#6652] RE: Array Intersect (&) question — rpmohn@... (Ross Mohn) 2000/11/29

aleksi.niemela@cinnober.com (Aleksi Niemel) wrote in

[#6723] Re: Array Intersect (&) question — Mathieu Bouchard <matju@...> 2000/12/01

> >Use a hash. Here's code to do both and more. It assumes that

[#6656] printing/accessing arrays and hashes — raja@... (Raja S.)

I'm coming to Ruby with a Python & Common Lisp background.

24 messages 2000/11/30

[ruby-talk:6440] Re: variable in regular expression

From: ts <decoux@...>
Date: 2000-11-18 16:57:42 UTC
List: ruby-talk #6440
>>>>> "m" == markus jais <mjais@web.de> writes:

m> old = ARGV[1]
m> new = ARGV[2]

 This is the same than perl (it begin at 0)

  old = ARGV[0]
  new = ARGV[1]

m> dir = Dir.new(".");
m> while line = dir.read
m>   next if line == "." or line == ".."
m>   puts line
m>   line.sub!(/old/,  new)    #!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!! Error

 You must write /#{old}/ to expand the variable 'old' otherwise ruby think
that it's the string "old"

m>   puts line
m> end


Guy Decoux









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