[#4766] Wiki — "Glen Stampoultzis" <trinexus@...>

21 messages 2000/09/04
[#4768] RE: Wiki — "NAKAMURA, Hiroshi" <nahi@...> 2000/09/04

Hi, Glen,

[#4783] Re: Wiki — Masatoshi SEKI <m_seki@...> 2000/09/04

[#4785] Re: Wiki — "NAKAMURA, Hiroshi" <nakahiro@...> 2000/09/05

Howdy,

[#4883] Re-binding a block — Dave Thomas <Dave@...>

16 messages 2000/09/12

[#4930] Perl 6 rumblings -- RFC 225 (v1) Data: Superpositions — Conrad Schneiker <schneik@...>

Hi,

11 messages 2000/09/15

[#4936] Ruby Book Eng. translation editor's questions — Jon Babcock <jon@...>

20 messages 2000/09/16

[#5045] Proposal: Add constants to Math — Robert Feldt <feldt@...>

15 messages 2000/09/21

[#5077] Crazy idea? infix method calls — hal9000@...

This is a generalization of the "in" operator idea which I

17 messages 2000/09/22

[#5157] Compile Problem with 1.6.1 — Scott Billings <aerogems@...>

When I try to compile Ruby 1.6.1, I get the following error:

15 messages 2000/09/27

[ruby-talk:5134] Re: Crazy idea? infix method calls

From: "Guy N. Hurst" <gnhurst@...>
Date: 2000-09-26 13:46:06 UTC
List: ruby-talk #5134
hal9000@hypermetrics.com wrote:
> 
> > |But I still think, as a special case, it woudl be a good idea if
> > |    x in y
> > |meant the same as
> > |   y.include? x
> > |
> > |It is "pretty" (IMO) in the same way that the for loop is pretty...
> >
> > It's possible, because 'in' is the reserved word, so that `x in y' is
> > not valid now.  Let us discuss about name, behavior, and
> > least-surprise-ness. ;-)
> >
> 
> Certainly let's discuss it then... ;)
> 
> I propose that the (pseudo) operator "in" (named as such) should
> result in a call to include? "under the hood," i.e., x in y or
> any arbitrary pair of objects x and y, should behave exactly the
> same as y.include? x, returning true or false and making possible
> syntax like: if node in binary_tree then ...
> 
> Now, is there any hidden catch, any unforeseen complication that
> I am unaware of?
> 

Well, I considered the following:

if node in binary_tree then print "found node!\n"; end
vs.
for node in binary_tree; print "current node is #{node}\n"; end

But such an ambiguity could probably be resolved in the grammar
for 'if' and 'for'.


I hope it would cover such things as:

for node in binary_tree; if node in binary_leaf then for i in 0..2; print "it's a leaf!\n"; end; end; end



Guy N. Hurst

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