From: nagachika00@...
Date: 2014-01-23T12:04:11+00:00
Subject: [ruby-core:60022] [Backport200 - Backport #8872] Case statements do not honor a refinement of the '===' method

Issue #8872 has been updated by Tomoyuki Chikanaga.

Assignee changed from Yukihiro Matsumoto to Tomoyuki Chikanaga

Hi,

I've told matz that this change introduced by r42923 was already released at 2.0.0p353 and matz decided to not to revert the changeset. (see https://twitter.com/yukihiro_matz/status/423500823788662784 )

I will backport r43913 to fix SEGV introduced at r42923.

Thanks.

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Backport #8872: Case statements do not honor a refinement of the '===' method
https://bugs.ruby-lang.org/issues/8872#change-44542

* Author: Jon Conley
* Status: Assigned
* Priority: Normal
* Assignee: Tomoyuki Chikanaga
* Category: 
* Target version: 
* ruby -v: -
----------------------------------------
=begin
Below, I've redefined the ((|===|)) method of symbol to always return true.  In ((|RefineTest#uses_refinement|)), I call ((|===|)) directly and the refined method is called.  In ((|RefineTest#does_not_use_refinement|)), the ((|===|)) method is called indirectly through a case statement.  If the refined ((|===|)) method was called, the result should be ((*'The refinement was used'*)), but this code currently returns ((*'The refinement was not used'*)).

 module RefineSymbol
   refine Symbol do
     def ===(other)
       true
     end
   end
 end
 
 using RefineSymbol
 
 class RefineTest
   def uses_refinement
     :a === :b
   end
 
   def does_not_use_refinement
     case :a
     when :b
       'The refinement was used'
     else
       'The refinement was not used'
     end
   end
 end
 
 rt = RefineTest.new
 rt.uses_refinement   # => true
 rt.does_not_use_refinement  # => expected 'The refinement was used' but got 'The refinement was not used'
=end




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