Re: Hash.new with a block?

On 3 Sep 2007, at 16:21, 7stud -- wrote:

> Alex Gutteridge wrote:
>> So short answer: Hash#[] calls Hash#default which in the case of Hash
>> objects with an associated Proc calls the Proc.
>>
>
> Thanks for the explanation.  So, is correct to assume that in the  
> source
> code for Hash#default there is a line somewhere that says something
> like:
>
> yield hash, key

Well proc.call(hash,key) really, which is almost (sort of) the same  
thing! Here is the source code from hash.c with my comments:

static VALUE rb_hash_default(argc, argv, hash){
     VALUE key;

     rb_scan_args(argc, argv, "01", &key);
     if (FL_TEST(hash, HASH_PROC_DEFAULT)) { //Test if default Proc  
is present
         if (argc == 0) return Qnil;
         return rb_funcall(RHASH(hash)->ifnone, id_call, 2, hash,  
key); //If so call the procs 'call' method
     }                                                                   
//with 'hash' and 'key' as args
     return RHASH(hash)->ifnone;
}


Alex Gutteridge

Bioinformatics Center
Kyoto University