From: Konrad Meyer <konrad@...>
Date: 2007-09-28T03:07:53+09:00
Subject: Re: Ruby's a = b vs PHP5's $obj1 =& $obj2

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Quoth SpringFlowers AutumnMoon:
> Just want to confirm Ruby's
>=20
>   a =3D b
>=20
> is the same as PHP5's
>=20
>   $obj1 =3D $obj2
>=20
> in other words, the reference is copied.
>=20
> While
>=20
>   $obj1 =3D& $obj2
>=20
> or
>=20
>   $obj1 =3D &$obj2
>=20
> in both PHP4 and PHP5 isn't the same as Ruby's   a =3D b
>=20
> $obj1 and $obj2 just become synonyms...
>=20
> and after
>=20
> $obj1 =3D new Foo("foo1");
> $obj2 =3D& $obj1
> $obj2 =3D new Foo("bar1");
>=20
> $obj1 and $obj2 have the same content, as they are just synonyms. (not a
> clone, not same reference, but just synonyms).  The "foo1" object is
> garbage-collected since no one is referencing it.
>=20
> this is giving me an initial headache... until maybe after i get used to
> it.

PHP's $var1 =3D& $var2 seems to be setting a reference to a reference. I th=
ink=20
ruby is more like PHP's $var1 =3D $var2, though I could be wrong.

HTH,
=2D-=20
Konrad Meyer <konrad@tylerc.org> http://konrad.sobertillnoon.com/

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