From: 7stud -- <dolgun@...>
Date: 2007-09-20T14:19:25+09:00
Subject: Re: How to parse a unicode url?

Dan The man wrote:
> I would really like to be able to do the following. Is this even
> possible?
> 
> Thanks,
> nerdytenor
> 
> uri = URI.parse('http://www.h旦ren.com') # not a real url (that I know
> of)
> URI::InvalidURIError: bad URI(is not URI?): http://www.h旦ren.com
>         from /usr/lib/ruby/1.8/uri/common.rb:432:in `split'
>         from /usr/lib/ruby/1.8/uri/common.rb:481:in `parse'
>         from (irb):26


You can do this:

require "uri"

url = "http://www.h旦ren.co"旦
enc_url = URI.encode(url)
puts enc_url


to get this:

http://www.h%C3%B6ren.co

which according to wikipedia here:

http://en.wikipedia.org/wiki/Percent-encoding

is a legal uri.  But when I do this:


require "uri"

url = "http://www.h旦ren.co"
enc_url = URI.encode(url)
puts enc_url

uri = URI.parse(enc_url)

I get this:

http://www.h%C3%B6ren.co
/usr/lib/ruby/1.8/uri/generic.rb:194:in `initialize': the scheme http 
does not accept registry part: www.h%C3%B6ren.co (or bad hostname?) 
(URI::InvalidURIError)
        from /usr/lib/ruby/1.8/uri/http.rb:46:in `initialize'
        from /usr/lib/ruby/1.8/uri/common.rb:484:in `new'
        from /usr/lib/ruby/1.8/uri/common.rb:484:in `parse'
        from r3test.rb:7


which as far as I can tell means that URI.parse() is broken.





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