From: Ruby Newbie <yeshvanthni@...>
Date: 2007-09-19T16:10:28+09:00
Subject: Is Block passed to 'times' efficient over for loop

Marcin Raczkowski wrote:
> Marcin Raczkowski wrote:
>>>   funk(n - 1) - (2 × funk(n - 2))  otherwise
>>> end
>>>
>> def rfib(n)
>>   b
>> 
>> 
>> class :)
>> 
>> 
> hmm i mistook Funkonacci with Fibonacci numbers and i guess you study on
>    university of texas ?
> 
> how fun :)
> 
> anyway:
> 
> 
> def rfunk(n)
>     return 0 if n<1
>     return 1 if n==1
>     rfunk(n-1) - 2*rfunk(n-2)
> end
> 
>   def ifunk(n)
>     return 0 if n<1
>     return 1 if n==1
>     a,b = 0,1
>     (n-1).times do 
>       a,b = b, b-2*a
>     end
>     b
>   end
> 
> here's version fur that funky numbers of yours, but if you have to ask
> ruby mailing list for such trivial home assigments you probably should
> switch curses right now, or #mayby peaople in US are just that stupid# Giving racial or personal comments on the members should not be allowed in this forum. Moderators,(If some exists )Please look into this post


To Understand a concept you dont need great problems to solve it cud be 
demonstrated in a simple problem. The solution you have given has been 
posted by the member already with a for loop.Do you mean using block 
over for loop improves the efficiency???????????????

Does using blocks improve it over using 'For'.Please give explanation.

-- 
Posted via http://www.ruby-forum.com/.