From: James Edward Gray II <james@...>
Date: 2007-09-18T00:27:25+09:00
Subject: Re: group array elements in groups of two

On Sep 17, 2007, at 10:18 AM, Emmanuel Oga wrote:

> A better way to do this? :
>
> arr= [1, 2, 3, 4, 5, 6, 7, 8]
> new= []
> while !arr.empty?
>   elem1, elem2= arr.pop, arr.pop
>   new << [elem2, elem1];
> end
> new.reverse!
>
> new= [[1, 2], [3, 4], [5, 6], [7, 8]]

 >> a = (1..8).to_a
=> [1, 2, 3, 4, 5, 6, 7, 8]
 >> require "enumerator"
=> true
 >> a.enum_slice(2).to_a
=> [[1, 2], [3, 4], [5, 6], [7, 8]]

Hope that helps.

James Edward Gray II