From: Robert Klemme Date: 2007-09-02T04:00:20+09:00 Subject: Re: Parsing query parameters from hyperlink On 01.09.2007 19:34, lrlebron@gmail.com wrote: > I am trying to parse strings like this > > > I need to get the cpnum value (555) > > I am using the following function > > def get_drugId(link) > arrParts = link.html.split('?') > cpnum = arrParts[1].split('&') > cpnumparts= cpnum[0].split("=") > drugId = cpnumparts[1] > end > > but I imagine there is a simpler way to do this. Also, I would like > something more flexible that would return all the query parameters (if > there are more than one) in an array or a hash. > > Any ideas? The std lib: require 'uri' irb(main):006:0> u=URI.parse("http://foo/bar?dodo=1&dada=2") => # irb(main):007:0> u.query => "dodo=1&dada=2" irb(main):008:0> u.query.split('&') => ["dodo=1", "dada=2"] ... robert