[ruby-talk:04458] Re: Few random notes

>>>>> "A" == Aleksi Niemel=E4?= <iso-8859-1> writes:

A> The statement of "last successful match" implicates that this is not the
A> behaviour and all 'p $1' statements on my example should print "matches
A> bar".

 Unlike perl, ruby don't have the notion of "last successful match"

A>   def foo(str)

 You must know that $~ is a *local* variable

A>     /(foo)/.match(str)
A>     bar(str)
A>     p $1      # the *latest* successful match has happened at bar
A>   end

 When you call a def, the first 2 local variables are $_ and $~


Guy Decoux