Re: inject problem

Hello=2C=20

I thought I solved this problem with this code :

def score(dice)
  total =3D 0=20
  h =3D Hash.new(0)
  dice.each {|el| dice[el] +=3D 1}

  dice.each {|number=2C count|
   if number =3D=3D 1 and count =3D=3D 3 then total =3D total + 1000 end
   if number =3D=3D 1 and count =3D=3D 6 then return 2000 end
   if number !=3D 1 and count =3D=3D 3 then total =3D total + 100 * count e=
nd
   if number !=3D 1 and count =3D=3D 6 then return 600 end
   if number =3D=3D 1 and (count > 3) then total =3D total + ( 100 + ( coun=
t - 3)) end
   if number =3D=3D 1 and (count < 3) then total =3D total   + 100 * count =
end
   if number =3D=3D 5 and (count > 3) then total =3D total + ( 50 * (count =
-3)) end
   if number =3D=3D 5 and (count < 3) then total =3D total +  50 * count en=
d
    }
  return total =20
end

But now I'm getting this error : undefined method `+' for nil:NilClass

Roelof


> Date: Tue=2C 25 Sep 2012 23:31:12 +0900
> From: [e-mail]
> Subject: Re: inject problem
> To: [e-mail]
>=20
> The first parameter of the "inject" block is always the intermediate=20
> result used for the aggregation. And the second is the current element.
>=20
> For example:
>=20
> # calculate sum of 1=2C 2=2C ...=2C 10 (in an inefficient way)
> sum =3D (1..10).inject do |intermediate_sum=2C integer|
>   intermediate_sum + integer
> end
>=20
> Or in your case:
>=20
> count =3D [1=2C 2=2C 1=2C 1]
> hash =3D count.inject({}) do |intermediate_hash=2C number|
>   intermediate_hash[number] +=3D 1 rescue intermediate_hash[number] =3D 1
>   intermediate_hash
> end
> puts hash
>=20
> --=20
> Posted via http://www.ruby-forum.com/.
>=20
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