From: 7stud -- Date: 2012-09-18T14:13:05+09:00 Subject: Re: Breaking Down the Block > >(It's the "b == 3" comment you made that I'm curious about.) > 1) If x = 2, then the statement result = x + 4, is equivalent to result = 6. 2) >> the conditional b == y[0][1] >> If ... you had results like this, >> >> y = [[10, 3], [30, 3], [20, 1], [40, 1]] What is y[0][1]? Now plug that value into this conditional: b == y[0][1] What do you get? -- Posted via http://www.ruby-forum.com/.