From: incag neato <lists@...>
Date: 2012-09-18T02:29:20+09:00
Subject: Re: Breaking Down the Block

Wow, so helpful. Thanks for taking so much of your time to explain. 
That must've taken at least an hour.

Now, the one question I have left pertains to the following (the tied 
values (double mode)).
____________________________________
> 7stud -- wrote in post #1076263:
> z = y.select {|a, b| b == y[0][1]}
> p z

> --output:--
> [[30, 2]]

> In this example, the conditional b == y[0][1] is equivalent to b == 2.
> If instead you had results like this,

> [[10, 3], [30, 3], [20, 1], [40, 1]]

> ...then the conditional would be b == 3, which just selects all the
> numbers that tie for the most appearances in the original array.
____________________________________

How is "b == y[0][1]" similar to "b == 2" ?
Do you mean the value in the sorted hash?

When I call "top_count = nums_with_frequs[0][1]" am I referring to the 
first key and value in the sorted hash "freq_for" (i.e. the var 
"nums_with_frequs")?

I've played around with it but I don't see how to use "b == 3" to arrive 
at the tied values.

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