Re: Time. to_military_time?

Mario Trento wrote in post #1050518:
> Is there any time function to get military time:
> eg.
>
> tim="0457"
> Time.striptime(time,....)       ==> 16:57

You can create a Time from individual fields:

irb(main):004:0> Time.mktime 2012,3,10,10,11,12
=> 2012-03-10 10:11:12 +0100

You can use that to parse yourself and create the time object, e.g.

def mt(s)
  raise "Not military #{s.inspect}" unless /\A(\d{2})(\d{2})\z/ =~ s
  h = ($1.to_i + 12) % 24 # correct?
  m = $2.to_i
  now = Time.now
  Time.mktime now.year, now.month, now.day, h, m
end

irb(main):021:0> mt "0457"
=> 2012-03-07 16:57:00 +0100

Of course you can also change that to work with numbers if you prefer

def mt(n)
  raise "Not military #{s.inspect}" unless Integer === n
  h, m = n.divmod 100
  h = (h + 12) % 24 # correct?
  now = Time.now
  Time.mktime now.year, now.month, now.day, h, m
end

irb(main):029:0> mt 457
=> 2012-03-07 16:57:00 +0100

Please note that numbers with leading 0 are octal:

irb(main):030:0> 0457
=> 303

> I found this sample below, it it works opposite, could not find any info
> how to get reverse so I'll get military format:

> def format_time(time)
>   # normalize time
>   time = time.to_s.rjust(4, '0') if time[0] !~ /[12]/
>   time = time.to_s.ljust(4, '0') if time[0] =~ /[12]/
>  puts "New_time=" + time.to_s
>
>   Time.strptime(time, '%H%M').strftime('%l:%M').strip
> end
>
> time = 1630
> p format_time(time) # "4:30"

That just looks awful since it works with strings instead using Time
properly.

Kind regards

robert

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