From: "Jan E." <lists@...>
Date: 2012-03-27T18:04:33+09:00
Subject: Re: sort array of strings with integers

Hi,

I assume you mean

b = %w[a1 a3 a2 a4 a7 a6 a5 a8 a9 a10]

Because what you wrote down isn't valid Ruby code.

Strings are ordered lexicographically by default. That is, the 
characters are compared one by one. This makes the string "a10" smaller 
than "a2", because the character "1" is smaller than "2" (the rest of 
the string is ignored).

If you want to change this behavious, you have to provide your own 
sorting rule:

b.sort_by! {|s| s[/\d+/].to_i}

Each element is passed to the block and then the block values are 
compared. In this case, the elements are compared by the "indices".

-- 
Posted via http://www.ruby-forum.com/.