From: Marcello Henrique <faraohh@...>
Date: 2011-01-15T11:10:50+09:00
Subject: Re: Ruby iterative depth.

Hi Abinoam,

Thanks for reply, actually the first number is 'id' and second
'parent_id', so correct is:
["1=>0",
  ["2=>1",
    ["3=>2",
      ["7=>3"]
    ],"5=>1","6=>1"
  ],"4=>0"
]

From source flat:
[ "1=>0","2=>1", "3=>2","4=>0","5=>1","6=>1","7=>3"]

The purpose is to use such as menu like this, based in example above:
<menu>
  <ul>
    <li class="sub">"1=>0"
      <ul>
        <li class="sub">"2=>1"
          <ul>
            <li class="sub">"3=>2"</li>
              <ul>
                <li>"7=>3"</li>
              </ul>
            </li>
          </ul>
        </li>
        <li>"5=>1"</li>
        <li>"6=>1"</li>
      </ul>
    </li>
    <li>"4=>0"</li>
  </ul>
</menu>

Thanks in advance!

On Fri, Jan 14, 2011 at 21:29, Abinoam Jr. <abinoam@gmail.com> wrote:
> Hi Marcello,
>
> For helping me understand your desired outcome I manually turned it
> into something more readable (just to read the nesting [] ).
>
> ["1=>0",["2=>1",["3=>2",["7=>3"]],["3=>2"]],["2=>1","5=>1","6=>1"]]
>
> arr[0] = "1=>0"
> arr[1] = ["2=>1", ["3=>2", ["7=>3"]], ["3=>2"]]
> arr[2] = ["2=>1", "5=>1", "6=>1"]
>
> Is this what you want?
>
> On Fri, Jan 14, 2011 at 11:54 AM, Marcello Henrique <faraohh@gmail.com> wrote:
>> Hello,
>>
>> Short question:
>>
>> How to make an iterative method of stack?
>>
>> Long explanation:
>> I'm trying to create an iterative method for following structure:
>>
>> class Obj
>>   attr_accessor: id,: parent_id
>>
>>   def initialize (id, parent_id)
>>     parent_id = @ parent_id
>>     @ id = id
>>   end
>>
>>   def to_s
>>     "id: # {@ id}, parent_id: @ # {parent_id} '
>>   end
>> end
>>
>> left = [Obj.new (1.0), Obj.new (2.1), Obj.new (3.2), Obj.new (4.0),
>> Obj.new (5.1), Obj new (6.1), Obj.new (7.3)]
>>
>> My challenge is to make an iterative method, see how far I got:
>>
>> def menu_iterative (menu)
>>   res = []
>>
>>   el1 = menu.shift
>>   res << el1
>>   while not menu.empty?
>>     res_aux = []
>>     for i in menu
>>       if el1.id == i.parent_id
>>         print el1, "==" i "* ", res_aux.index (el1), "\ n"
>>         res_aux << i
>>         el1 = menu.delete (i)
>>         retry
>>       else
>>         print el1, "! =" i, "\ n"
>>       end
>>     end
>>     res << res_aux unless res_aux.empty?
>>     puts
>>     el1 = menu.shift
>>     res << el1
>>   end
>>   return res
>> end
>>
>> puts "result:"
>> pp menu_iterative (left_it)
>>
>> I wish the outcome was:
>>
>> [*,
>>  [#<Obj:0x7f35b48cab18 @id=2, @parent_id=1>,
>>  [#<Obj:0x7f35b48caaf0 @id=3, @parent_id=2>,
>>   [#<Obj:0x7f35b48caa50 @id=7, @parent_id=3>]],
>>  [#<Obj:0x7f35b48caaf0 @id=3, @parent_id=2>]],
>>  [#<Obj:0x7f35b48cab18 @id=2, @parent_id=1>,
>>  #<Obj:0x7f35b48caaa0 @id=5, @parent_id=1>,
>>  #<Obj:0x7f35b48caa78 @id=6, @parent_id=1>]]
>>
>> It seems that the problem is attribution without stack, correct?
>> I'm attaching all I did.
>>
>> Thanks for any help.
>> --
>> Marcello Henrique
>> Blog - http://faraohh.wordpress.com
>> Associação Software Livre de Goiás (www.aslgo.org.br)
>> Cercomp - UFG (www.cercomp.ufg.br)
>>
>
>



-- 
Marcello Henrique
Blog - http://faraohh.wordpress.com
Associação Software Livre de Goiás (www.aslgo.org.br)
Cercomp - UFG (www.cercomp.ufg.br)