[#388484] ruby-doc.org has been updated — James Britt <james.britt@...>

Ruby-doc.org has been updated.

22 messages 2011/10/03

[#388492] Operator Overloading — Thescholar Thescholar <thescholar@...>

Let's suppose I have a class like this one and then I create two

28 messages 2011/10/04
[#388515] Re: Operator Overloading — "Darryl L. Pierce" <mcpierce@...> 2011/10/04

On 10/04/2011 01:11 AM, Thescholar Thescholar wrote:

[#388518] Re: Operator Overloading — Brian Candler <b.candler@...> 2011/10/04

Darryl Pierce wrote in post #1024950:

[#388519] Re: Operator Overloading — "Darryl L. Pierce" <mcpierce@...> 2011/10/04

On 10/04/2011 10:03 AM, Brian Candler wrote:

[#388520] Re: Operator Overloading — Adam Prescott <adam@...> 2011/10/04

On Tue, Oct 4, 2011 at 3:53 PM, Darryl L. Pierce <mcpierce@gmail.com> wrote:

[#388523] Local vs method vs instance (was: Operator Overloading) — "Darryl L. Pierce" <mcpierce@...> 2011/10/04

On 10/04/2011 11:11 AM, Adam Prescott wrote:

[#388526] Re: Local vs method vs instance (was: Operator Overloading) — Jes俍 Gabriel y Gal疣 <jgabrielygalan@...> 2011/10/04

On Tue, Oct 4, 2011 at 5:31 PM, Darryl L. Pierce <mcpierce@gmail.com> wrote:

[#388558] question about method — "Joseph S." <musician_joe777@...>

AC = 14

12 messages 2011/10/04

[#388595] Read thru Csv file and store it in variables — ideal one <idealone5@...>

HI All,

9 messages 2011/10/05

[#388601] How to output an instance's type — Viaduct Productions <lists@...>

Hiya folks.

21 messages 2011/10/05
[#388603] Re: How to output an instance's type — Kassym Dorsel <k.dorsel@...> 2011/10/05

By type you want the variables class ?

[#388610] Re: How to output an instance's type — Viaduct Productions <lists@...> 2011/10/05

Hi Kassym. Thanks for the post.

[#388612] Re: How to output an instance's type — Kassym Dorsel <k.dorsel@...> 2011/10/05

Viaduct Productions wrote in post #1025201:

[#388636] Re: How to output an instance's type — luke gruber <luke.gru@...> 2011/10/06

>How do I output the type of a variable?

[#388644] Re: How to output an instance's type — Viaduct Productions <lists@...> 2011/10/06

Hi Luke. Thanks for the reply.

[#388658] Re: How to output an instance's type — Phillip Gawlowski <cmdjackryan@...> 2011/10/06

A: Because it messes with the readability of the reply, since the

[#388650] Cheapest way to host low-traffic small-footprint Rails app? — Intransition <transfire@...>

I have a commercial Radiant-based website that I manage for a small-

18 messages 2011/10/06
[#388653] Re: Cheapest way to host low-traffic small-footprint Rails app? — Phillip Gawlowski <cmdjackryan@...> 2011/10/06

On Thu, Oct 6, 2011 at 2:47 PM, Intransition <transfire@gmail.com> wrote:

[#388660] Re: Cheapest way to host low-traffic small-footprint Rails app? — Dan Nachbar <dan@...> 2011/10/06

On Oct 6, 2011, at 8:53 AM, Phillip Gawlowski wrote:

[#388662] Re: Cheapest way to host low-traffic small-footprint Rails app? — Viaduct Productions <lists@...> 2011/10/06

What do people consider "cheap"? You want scalability? Support?

[#388666] Re: Cheapest way to host low-traffic small-footprint Rails app? — Dan Nachbar <dan@...> 2011/10/06

On Oct 6, 2011, at 9:58 AM, Viaduct Productions wrote:

[#388812] require -- looking in rubygems, now "." — "charles a." <charles.agriesti@...>

irb

11 messages 2011/10/09

[#388855] why does `a + f b` not parse? — Martin DeMello <martindemello@...>

ruby-1.9.2-p0 > 2 + sqrt 5

18 messages 2011/10/11
[#388857] Re: why does `a + f b` not parse? — Wayne Brissette <waynefb@...> 2011/10/11

[#388858] Re: why does `a + f b` not parse? — Dave Aronson <rubytalk2dave@...> 2011/10/11

On Tue, Oct 11, 2011 at 06:32, Wayne Brissette <waynefb@earthlink.net> wrote:

[#388861] Re: why does `a + f b` not parse? — Phillip Gawlowski <cmdjackryan@...> 2011/10/11

On Tue, Oct 11, 2011 at 1:02 PM, Dave Aronson

[#388862] Re: why does `a + f b` not parse? — jake kaiden <jakekaiden@...> 2011/10/11

Phillip Gawlowski wrote in post #1026042:

[#388864] Re: why does `a + f b` not parse? — Bartosz Dziewoński <matma.rex@...> 2011/10/11

Yes, I think we all know that; the question is, why does 2 + sqrt(5)

[#388881] gem directory not find — Sam Porwal <pawan.porwal@...>

Hi All,

11 messages 2011/10/11

[#388945] What’s the best way of checking if an argument has been given or not? — Nikolai Weibull <now@...>

Hi!

19 messages 2011/10/14
[#388950] Re: What’s the best way of checking if an argument has been given or not? — jake kaiden <jakekaiden@...> 2011/10/14

...probably not the *best* way, but this works:

[#388952] Re: What’s the best way of checking if an argument has been given or not? — Bartosz Dziewoński <matma.rex@...> 2011/10/14

You can use this syntax, too. "args" becomes an array of all arguments given.

[#388954] Re: What’s the best way of checking if an argument has been given or not? — Nikolai Weibull <now@...> 2011/10/14

On Fri, Oct 14, 2011 at 15:29, Bartosz Dziewoński <matma.rex@gmail.com> wrote:

[#388958] Re: What’s the best way of checking if an argument has been given or not? — Chris Hulan <chris.hulan@...> 2011/10/14

You could do it as a wrapper:

[#388961] Re: What’s the best way of checking if an argument has been given or not? — Nikolai Weibull <now@...> 2011/10/14

On Fri, Oct 14, 2011 at 15:51, Chris Hulan <chris.hulan@gmail.com> wrote:

[#388962] Re: What’s the best way of checking if an argument has been given or not? — Chris Hulan <chris.hulan@...> 2011/10/14

You said you didn't want to manually do it, this lets the interpreter

[#388970] Re: What’s the best way of checking if an argument has been given or not? — luke gruber <luke.gru@...> 2011/10/14

Hmm, if you really don't want to use the splat *args, you could create a

[#388972] Re: What’s the best way of checking if an argument has been given or not? — Jens Wille <jens.wille@...> 2011/10/14

luke gruber [2011-10-14 17:15]:

[#388947] Beginning — "Junayeed Ahnaf Nirjhor" <zombiegenerator@...>

Hello,

19 messages 2011/10/14

[#389025] writing a poem backwards or in reverse order — Teresa Nguyen <s-unguyen2@...>

i would like to write a poem using nano and through ruby I would like to

18 messages 2011/10/16
[#389036] Re: writing a poem backwards or in reverse order — Jes俍 Gabriel y Gal疣 <jgabrielygalan@...> 2011/10/16

On Sun, Oct 16, 2011 at 2:04 AM, Teresa Nguyen

[#389026] 'gem install' help please — Kaye Ng <sbstn26@...>

Hi.

18 messages 2011/10/16

[#389037] Ruby and threading — Carter Cheng <cartercheng@...>

Hello,

32 messages 2011/10/16
[#389038] Re: Ruby and threading — Josh Cheek <josh.cheek@...> 2011/10/16

On Sun, Oct 16, 2011 at 3:50 AM, Carter Cheng <cartercheng@gmail.com> wrote:

[#389195] Re: Ruby and threading — Josh Cheek <josh.cheek@...> 2011/10/19

On Sun, Oct 16, 2011 at 4:03 AM, Josh Cheek <josh.cheek@gmail.com> wrote:

[#389100] IDE — "Junayeed Ahnaf Nirjhor" <zombiegenerator@...>

Hello,

13 messages 2011/10/17

[#389340] security thesis advice — Jorge Bo <jorgebo10@...>

Hi,

19 messages 2011/10/22

[#389465] Modify only a .rb file, but not other .rb files, while still extending core classes? — Marc Heiler <shevegen@...>

Given is a small .rb file.

8 messages 2011/10/26

[#389553] "A" and "an" articles in front of words — Faith Tarcha <faith@...>

Hello guys, I have two objects that consist of arrays and I am suppose

29 messages 2011/10/29
[#389587] Re: "A" and "an" articles in front of words — jake kaiden <jakekaiden@...> 2011/10/31

hi Faith,

[#389598] Re: "A" and "an" articles in front of words — Dave Aronson <rubytalk2dave@...> 2011/10/31

On Sun, Oct 30, 2011 at 22:23, jake kaiden <jakekaiden@yahoo.com> wrote:

[#389789] Re: "A" and "an" articles in front of words — steve ross <cwdinfo@...> 2011/11/06

Sorry to be late to the party on this one, but a regex seems a bit of a big hammer. How about:

[#389791] Re: "A" and "an" articles in front of words — Hassan Schroeder <hassan.schroeder@...> 2011/11/06

On Sun, Nov 6, 2011 at 12:59 PM, steve ross <cwdinfo@gmail.com> wrote:

[#389795] Re: "A" and "an" articles in front of words — Peter Camilleri <pdc.cse@...> 2011/11/06

Indeed. My understanding is that the usage of a/an depends on the

[#389859] Re: "A" and "an" articles in front of words — Gonçalo C. Justino <goncalo.justino@...> 2011/11/08

> Indeed. My understanding is that the usage of a/an depends on the

[#389590] Vim Ruby Config — "Junayeed Ahnaf Nirjhor" <zombiegenerator@...>

Hello,

13 messages 2011/10/31

Re: translation from Python

From: Marc Heiler <shevegen@...>
Date: 2011-10-13 06:08:39 UTC
List: ruby-talk #388924
Always remember that while python has sane syntax (compared to
perl and php), its inner logic does not work in a 1:1
translation into ruby code.

So you must adapt it to fit the ruby model. But usually this is
trivial and straight forward.

The first thing you should do is use the same method name but
adapt it to ruby.

Something like:
  def getwordcounts(url):

Would then become:

  def getwordcounts(url)
  end

Next thing is to understand your data structures.

I do not know python really but something like this here:

  wc[word]+=1

Seems to update the dictionary, at the keyword word position,
by + 1.

With hash.default = you can specify a default value for
your keys in a hash, in ruby.

Whenever you see a loop from python, like "for x in y", the
ruby way is usually to use .each instead on an enumerator.

  array.each do |line|
    # do something here
  end

Or shorter, rather than do/end, to use the {} block syntax.

"I'm pretty vague about "#HERE!" parts."

I don't know what the #HERE! means either. But it is clearly
a comment. Perhaps the one who wrote so wanted to jump from
#HERE! to #HERE! ?

""wc" will be an array containing the words picked up...?"

I believe wc typically is short for "word count".

And with wc[word]+=1 you count the word, kind of. :D

For ruby, I tend to use something like this to count the words
in a string:

class String

  # 
========================================================================= 
#
  # === word_count
  # Counts word frequencies. Returns a hash.
  # Usage examples:
  #   x = %{ Dogs cat? cat? cat dog dog dog cat dog eagle dog 
dogs}.word_count
  #        => { "cat"=>2, "dogs"=>2, "eagle"=>1, "dog"=>5, "cat?"=>2 }
  # 
========================================================================= 
#
  def word_count
    hash = Hash.new(0)
    downcase.scan(/\w+\??/) { |word| hash[word] += 1 }
    return hash
  end

end

(Of course you can also just use a method instead of extending class 
String,
and pass the string to that method as argument.)


"there are "word" and "words" in the code but "word" does not
appear defined although it's used locally"

But it looks as if word is defined:

  for word in words:

See? The word variable appears there. In ruby, this would become 
something
like this here:

  array.each { |word| }

-- 
Posted via http://www.ruby-forum.com/.

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