From: Phillip Gawlowski <cmdjackryan@...>
Date: 2011-10-12T04:08:11+09:00
Subject: Re: why does `a + f b` not parse?

On Tue, Oct 11, 2011 at 4:50 PM, Robert Klemme
<shortcutter@googlemail.com> wrote:
>
>  I mean "a b" can never by "a.b" but must always be
> "a(b)".  That leaves only "2.+(sqrt(5))" on your list (item 2, same as
> item 5).

What about 2.+(2)? It's equivalent to 2 + 2, after all, and not 2(+(2)).

"never" is a strong word to use, especially in Ruby. ;)

-- 
Phillip Gawlowski

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A method of solution is perfect if we can forsee from the start,
and even prove, that following that method we shall attain our aim.
              -- Leibniz