From: Robert Klemme <shortcutter@...>
Date: 2011-10-17T16:57:57+09:00
Subject: Re: Ruby functions to split numbers

On Fri, Oct 14, 2011 at 11:54 PM, ideal one <idealone5@hotmail.com> wrote:
> Ian M. Asaff wrote in post #1026669:
>> ruby-1.9.2-p290 :010 > a = "01234567"
>>  => "01234567"
>> ruby-1.9.2-p290 :011 > var1,var2 = [a[0,3],a[3,5]]
>>  => ["012", "34567"]
>> ruby-1.9.2-p290 :012 > var1
>>  => "012"
>> ruby-1.9.2-p290 :013 > var2
>>  => "34567"
>>
>> keep in mind that a number with a leading zero makes ruby think the base
>> is
>> octal:
>>
>> ruby-1.9.2-p290 :019 > 012
>>  => 10
>>
>> hope that helps.

>             How can i auto increment the number, i tried doing
> something like this...
> var1 is always constant, but i want to autoincrement var2
>
> value = var2 + 1  #  iam getting Cannot convert Fixnum to String Error.
> is something like this works var2++, not tried this in ruby.
> Preserve leading Zero and also autoincrement..

I am still not sure I get what you really want to do with those
numbers.  What exactly is your input (String or a Fixnum) and what do
you want to do with it?

Here is one more way to split and assign to local variables:

irb(main):009:0> s = "1234567"
=> "1234567"
irb(main):010:0> /\A(?<v1>\d{1,3})(?<v2>\d{5})\z/ =~ s
=> 0
irb(main):011:0> v1
=> "12"
irb(main):012:0> v2
=> "34567"

But if your input is already numeric other approaches are usually better, e.g.

irb(main):013:0> n = 1234567
=> 1234567
irb(main):014:0> v1 = n / 100000
=> 12
irb(main):015:0> v2 = n % 100000
=> 34567

(Assuming we're talking about decimal representation.)

Kind regards

robert

-- 
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