From: Josh Cheek <josh.cheek@...>
Date: 2011-10-15T10:50:21+09:00
Subject: Re: Ruby functions to split numbers

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On Fri, Oct 14, 2011 at 4:54 PM, ideal one <idealone5@hotmail.com> wrote:

> Ian M. Asaff wrote in post #1026669:
> > ruby-1.9.2-p290 :010 > a = "01234567"
> >  => "01234567"
> > ruby-1.9.2-p290 :011 > var1,var2 = [a[0,3],a[3,5]]
> >  => ["012", "34567"]
> > ruby-1.9.2-p290 :012 > var1
> >  => "012"
> > ruby-1.9.2-p290 :013 > var2
> >  => "34567"
> >
> > keep in mind that a number with a leading zero makes ruby think the base
> > is
> > octal:
> >
> > ruby-1.9.2-p290 :019 > 012
> >  => 10
> >
> > hope that helps.
> >
> > ian
>
> Hello there,
>             How can i auto increment the number, i tried doing
> something like this...
> var1 is always constant, but i want to autoincrement var2
>
> value = var2 + 1  #  iam getting Cannot convert Fixnum to String Error.
> is something like this works var2++, not tried this in ruby.
> Preserve leading Zero and also autoincrement..
>
> Cheers
>
> --
> Posted via http://www.ruby-forum.com/.
>
>
Strings have implemented on them the method "next" which, for numerical
strings, seems to respect numerical iteration

n = '0'
15.times do
  n = n.next # => "1", "2", "3", "4", "5", "6", "7", "8", "9", "10", "11",
"12", "13", "14", "15"
end


I'm not 100% sure that this is compatible across all versions of Ruby, you
should definately have a test to make sure that it increments them as you
expect. You should also consider what happens when you have something like
"999", is it supposed to go to "1000", which would cause it to gain a digit?
If not, you'll need to add special handling for that situation.

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