[ruby-talk:01115] Re: Infinite loop

Hi,

In message "[ruby-talk:01113] Re: Infinite loop"
    on 00/01/12, ts <[e-mail]> writes:

|Y>   * a.hash == b.hash where a.eql?(b) is true.
|
| I've not understood, sorry. Do you mean 
|
| 1) if a.eql?(b) then a.hash == b.hash
|
| or
|
| 2) if a.hash == b.hash then a.eql?(b) is true

The former, i.e. forall a and b satisfy a.eql?(b), a.hash and b.hash
should have same values.  But if a.hash and b.hash have same hash
values, a.eql?(b) may not be true.

| This don't work for the first case with [1, 2, [1, 2]] and [1, 2, [1, 2]]

Yes, you are right.  I must think more deeply about how to get hash
values for arrays.  sigh.

							matz.