[ruby-core:74322] [Ruby trunk Bug#12073][Closed] local variable interferes with keyword arguments

Issue #12073 has been updated by Nobuyoshi Nakada.

Description updated
Status changed from Open to Closed
Backport changed from 2.0.0: UNKNOWN, 2.1: UNKNOWN, 2.2: UNKNOWN, 2.3: UNKNOWN to 2.1: REQUIRED, 2.2: REQUIRED, 2.3: REQUIRED

Sean Linsley wrote:
> This is also an issue with array destructuring:

You are warned.

```
$ ruby -w -e 'def a(*b); b; end' -e 'a=[1,2,3]' -e 'a *a'
-e:3: warning: `*' after local variable or literal is interpreted as binary operator
-e:3: warning: even though it seems like argument prefix
-e:3: warning: possibly useless use of * in void context
-e:3:in `*': no implicit conversion of Array into Integer (TypeError)
	from -e:3:in `<main>'
```

----------------------------------------
Bug #12073: local variable interferes with keyword arguments
https://bugs.ruby-lang.org/issues/12073#change-57442

* Author: Josh Cheek
* Status: Closed
* Priority: Normal
* Assignee: 
* ruby -v: ruby 2.3.0p0 (2015-12-25 revision 53290) [x86_64-darwin13]
* Backport: 2.1: REQUIRED, 2.2: REQUIRED, 2.3: REQUIRED
----------------------------------------
This code causes a syntax error:

~~~ruby
def a(b:)
  b
end
a = 1
a b: 9
 
# !> program.rb:5: syntax error, unexpected ':', expecting end-of-input
# !> a b: (9)
# !>     ^
~~~

However, if we remove the local assignment it works

~~~ruby
def a(b:)
  b
end
a b: 9 # => 9
~~~

Or if we use parentheses it works

~~~ruby
def a(b:)
  b
end
a = 1
a(b: 9) # => 9
~~~

Or if we use non-keyword arguments it works

~~~ruby
def a(b)
  b
end
a = 1
a 9 # => 9
~~~



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