[#11852] continuations in Ruby 1.9? — David Flanagan <david@...>
In a comment on my recent blog post
On 8/6/07, David Flanagan <david@davidflanagan.com> wrote:
[#11860] Is this really what we want? — James Edward Gray II <james@...>
I'm investigating some recent breakage in FasterCSV and have tracking
Hi,
[#11871] ruby-openssl: == incorrect for X509-Subjects — Hadmut Danisch <hadmut@...>
Hi,
[#11876] priorities of newly-created threads — David Flanagan <david@...>
Hi,
Hi,
[#11886] Core dump with simple web scraper when run via cron — Daniel Berger <Daniel.Berger@...>
Hi all,
[#11890] Ruby and Solaris door library — "Hiro Asari" <asari.ruby@...>
Hi, there. This is my first patch against ruby. I think I followed
Hiro Asari wrote:
On 8/13/07, Daniel Berger <djberg96@gmail.com> wrote:
> -----Original Message-----
On 8/15/07, Berger, Daniel <Daniel.Berger@qwest.com> wrote:
[#11893] UDP sockets raise exception on MIPS platform — Brian Candler <B.Candler@...>
I am running ruby-1.8.6 under OpenWrt (*), which is a small MIPS platform
[#11894] IO#seek and whence problem — Bertram Scharpf <lists@...>
[#11899] pack/unpack 64bit Integers — Hadmut Danisch <hadmut@...>
Hi,
On Wed, Aug 15, 2007 at 06:50:01AM +0900, Hadmut Danisch wrote:
On Wed, Aug 15, 2007 at 02:45:20PM +0900, Brian Candler wrote:
On Fri, Aug 17, 2007 at 05:17:09PM +0200, Hadmut Danisch wrote:
Dumb question of the day: are Kernel#proc and Kernel#lambda identical?
> Dumb question of the day: are Kernel#proc and Kernel#lambda identical?
[#11900] missing bison, gperf not detected, do I need ruby to build ruby? — "Gabor Szabo" <szabgab@...>
Hi,
On Wed, 15 Aug 2007, Gabor Szabo wrote:
> > It seems ./configure did not detect the fact that bison was missing from
[#11930] Bug in select? — "Robert Dober" <robert.dober@...>
Hi
[#11945] Smoke testing Ruby — "Gabor Szabo" <szabgab@...>
Hi,
On 8/21/07, Gabor Szabo <szabgab@gmail.com> wrote:
Ruby used to have the Triple-R project based on Rubicon: see
Hugh Sasse wrote:
[#11947] Splatting MatchData bug? — Jos Backus <jos@...>
$ /tmp/ruby-1.9/bin/ruby -v
[#11948] Fibers in Ruby 1.9? — David Flanagan <david@...>
I just noticed that my ruby1.9 build of August 17th includes a Fiber
David Flanagan wrote:
On 8/22/07, Daniel Berger <djberg96@gmail.com> wrote:
On Wed, 22 Aug 2007 20:50:12 +0900, "Francis Cianfrocca" <garbagecat10@gmail.com> wrote:
On 8/22/07, MenTaLguY <mental@rydia.net> wrote:
On Thu, 23 Aug 2007 00:57:01 +0900, "Francis Cianfrocca" <garbagecat10@gmail.com> wrote:
[#11960] coroutines with Fiber::Core — David Flanagan <david@...>
The following code works on Linux with today's snapshot of 1.9:
Hi,
[#11981] Inverse Square Root — "Dave Pederson" <dave.pederson@...>
Hello-
[#11988] String#length not working properly in Ruby 1.9 — "Vincent Isambart" <vincent.isambart@...>
I saw that Matz just merged his M17N implementation in the trunk.
Hi,
On Sat, 25 Aug 2007 10:54:20 +0200, Yukihiro Matsumoto
Hi,
On 8/25/07, Yukihiro Matsumoto <matz@ruby-lang.org> wrote:
Hi,
On 8/25/07, Yukihiro Matsumoto <matz@ruby-lang.org> wrote:
[#12025] how to build ruby on vms — "toni" <toni@...>
Hi,
[#12040] Pragmas in Ruby 1.9 — David Flanagan <david@...>
Hi,
[#12042] Encodings of string literals; explicit codepoint escapes? — David Flanagan <david@...>
This message contains queries that probably only Matz can answer:
Hi,
Yukihiro Matsumoto wrote:
On 8/31/07, Yukihiro Matsumoto <matz@ruby-lang.org> wrote:
Re: Inverse Square Root
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Dave Pederson wrote:
> I was wondering if it is possible to include the quake fast inverse
> square root function in ruby?
I oppose this for three reasons:
1. Computing inverse square roots is already possible in Ruby with just
one operation using the exponentiation operator
ruby -e 'puts 0.0025 ** -0.50'
20.0
or with two operations using division and Math.sqrt
ruby -e 'puts 1.0 / Math.sqrt(0.0025)'
20.0
2. The fast computation of an inverse square root is too rarely used to
be implemented as part of a general purpose language.
3. The algorithm is mediocre at best. Better ones with faster
convergence are available - without much search one can find one that
converges cubically (the one you proposed only converges
quadratically):
Task: Given $S$ compute $\frac{1}{\sqrt{S}}$.
Solution: Starting from $x_0$ let
\begin{equation}
y_n = S \cdot {x_n}^2,
\end{equation}
and
\begin{equation}
x_{n+1} = \frac{x_n}{8} \cdot (15 - y_n \cdot (10 - 3 y_n))
\end{equation}
which can be evaluated in this way:
void main() {
double s = 0.0025;
double x = 0.0, xn = 1.0, yn;
while (x != xn) {
yn = s * xn * xn;
x = xn;
xn *= 0.125 * (15.0 - yn * (10.0 - 3.0 * yn));
printf("%.16f\n", xn);
}
}
This algorithm can be found in Wikipedia at
http://en.wikipedia.org/wiki/Methods_of_computing_square_roots
Please note that 20 = sqrt(400) = isqrt(1/400) = isqrt(0.0025).
Have fun,
Josef 'Jupp' Schugt
- --
Blog available at http://www.mynetcologne.de/~nc-schugtjo/blog/
PGP key with id 6CC6574F available at http://wwwkeys.de.pgp.net/
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