Re: Require bug confirmation: possible 'times' method error

I think you're seeing expected behavior here.

A Ruby method will return the value of the last expression in the method,
unless there is an earlier return statement.

In the interest of "teaching you to fish", I'll just ask a couple of
leading questions:

What happens if you use 5.times?

What happens if you use 7.times?

Does that help?

Randy

On Wed, Feb 8, 2012 at 8:56 AM, Tom Clarke <[e-mail]> wrote:

> Hi all,
>
> First time posting here. I'm a Ruby newbie, so apologies if this question
> sounds dumb.
>
> I've found something I'm unable to explain. It's either a 'bug' or a
> confusing feature. See code below (taken from rubylearning.com):
> ---
> "# p019mtdarry.rb
>
> # if you give return multiple parameters,
> # the method returns them in an array
> # The times method of the Integer class iterates block num times,
> # passing in values from zero to num-1
>
> def mtdarry
>  10.times do |num|
>  square = num * num
>  return num, square if num > 5
>  end
> end
>
>
> # using parallel assignment to collect the return value
> num, square = mtdarry
>
> puts num
> puts square"
> ---
> The output is meant to be as follows:
> ---
> ">ruby p019mtdarry.rb
> 6
> 36
> >Exit code: 0"
> ---
> This is the output for the code above. However, if I change 10.times to
> 6.times, the 'puts num' output is 6, and the square output is blank.
>
> The reason this is odd is, if the values for num go from 0 to 5, then the
> output of puts num should be 5. However, as the output of puts num is 6,
> then the puts square output should be 36, but instead it is blank.
>
> I've tested this on both Ruby 1.9.2 and 1.9.3 (p0). My question is, should
> I raise this as a bug or have I missed something in my program analysis?
>
> Thanks,
> Tom
>



-- 
Randy Coulman
[e-mail]
Twitter: @randycoulman