From: Josh Cheek <josh.cheek@...>
Date: 2012-02-09T17:05:17+09:00
Subject: Re: A better way implement "it" the ruby way

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On Wed, Feb 8, 2012 at 10:36 AM, Bravo Man <thebravoman@gmail.com> wrote:

>
> I am sure there are plenty of ways to implement this in Ruby more
> clearly in a number of lines. It would be great if you could share your
> ideas for the implementation.
>
>
As others suggested,  rand(...).to_s(...).rjust(...) is obviously the best
way, but here is another option:

3.times.map { [*0..9,*'A'..'Z'].sample }.join


3.times will create an enumerator -- an object waiting to be invoked with a
block that it will then call 3 times.

Then we convert it to another enumerator with map, which, for each of the
times, will invoke the block we give it and populate the result into an
array.

In the block, the 0..9 and 'A'..'Z' are ranges of digits and characters.
Placing the splat in front of them turns them into arrays (note that in
many places you have to surround this with parens, we don't here because
we're in an array literal). Calling `sample` on this will choose one of its
elements at random, and since this is the last expression in the block, it
will be returned.

All this so far gives us an array of size 3 with the digits and characters
we want, we call `join` to turn them into a string.

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