From: Bravo Man <thebravoman@...>
Date: 2012-02-09T01:36:24+09:00
Subject: A better way implement "it" the ruby way

Hi,

I come from the world of other programming languages and in the process
of learning Ruby I am trying to implement a few algorithms.

It would be great if you could assist me with proposal for implementing
it in a more "ruby" way tham directly following the pattern from "java"
for example.

I would like to convert integers to strings where the strings are of the
form XXX. X is a digit from 0 to 9 or a letter from A to Z. So 11 gets
converted to 00B. 37 is 010. And 46656 gets converted to ZZZ.

An example for the algorithm is:

public String generateKey(int number) {
    StringBuilder builder = new StringBuilder();
    int mod = number % 36;
    int k = number;
    do {
      appendSymbol(mod, builder);
      k = k / 36;
      mod = k % 36;
    } while (k != 0);
    if (builder.length() < 3)
      appendSymbol(mod, builder);
    if (number < 36)
      builder.append("0");
    return builder.reverse().toString();
  }
  private char convertToLetter(int start) {
    int number = start - 10 + 'A';
    return (char) number;
  }

  private void appendSymbol(int i, StringBuilder builder) {
    if (i < 10)
      builder.append(Integer.toString(i));
    else
      builder.append(convertToLetter(i));
  }

I am sure there are plenty of ways to implement this in Ruby more
clearly in a number of lines. It would be great if you could share your
ideas for the implementation.

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