From: Eric Christopherson <echristopherson@...>
Date: 2012-02-04T02:32:24+09:00
Subject: Re: Basic Ruby performance

On Fri, Feb 3, 2012 at 11:17 AM, Dmitry Nikiforov <dniq@dniq-online.com> wrote:
> Here's a question: when I say "for a in ( 0..1E8 )" - does Ruby create
> an array and populate is with values from 0 through 1E8, or does it
> merely create a counter similar to "for( a = 0; a<=1e8, a++ )" ?

It might make a counter-based loop internally, but at a higher level
it translates it into an iterator using Enumerable#each. The iterator
knows how to return the next number in the range each time. It doesn't
create an array with 1E8+1 elements.