From: Kenichi Kamiya <kachick1@...>
Date: 2012-02-04T12:20:20+09:00
Subject: Re: 4 random numbers take highest 3 and add them together.

Hi, h4y4shi

I think that error from some causes.

* while   # not closed(and not need)
* when  # when only in case
* |         # points different meanings, use "||" or "or" for this case

below codes tested in 1.9.3p0

ex)

stats1a = (rand(6) + 1)
stats1b = (rand(6) + 1)
stats1c = (rand(6) + 1)
stats1d = (rand(6) + 1)
gstats1a = 0
gstats1b = 0
gstats1c = 0
gstats1d = 0

if (stats1a>stats1b) || (stats1a>stats1c) || (stats1a>stats1d)
  gstats1a = stats1a
end

if (stats1b>stats1a) || (stats1b>stats1c) || (stats1b>stats1d)
  gstats1b = stats1b
end

if (stats1c>stats1b) || (stats1c>stats1a) || (stats1c>stats1d)
  gstats1c = stats1c
end

if (stats1d>stats1b) || (stats1d>stats1c) || (stats1d>stats1a)
  gstats1d = stats1d
end

mstr = gstats1a + gstats1b + gstats1c + gstats1d

ex2)
# another approach

stats = 4.times.map{rand(6) + 1}
min = stats.min
p stats.reject{|n|n == min}.inject(:+)

2012/2/4 h4y4shi 13bladex <serpentinexcubed@gmail.com>:
> I want to get 4 random numbers. The numbers will be between 1-6. I want
> to disregard the smallest number and add the three biggest numbers
> together. So far I wrote some ruby that I thought would do this but I
> keep getting an error.
>
> statsrand = 0
> while statsrand == 0
> stats1a = (rand(6) + 1)
> stats1b = (rand(6) + 1)
> stats1c = (rand(6) + 1)
> stats1d = (rand(6) + 1)
> gstats1a = 0
> gstats1b = 0
> gstats1c = 0
> gstats1d = 0
> when (stats1a>stats1b) | (stats1a>stats1c) | (stats1a>stats1d)
>  gstats1a = stats1a
> when (stats1b>stats1a) | (stats1b>stats1c) | (stats1b>stats1d)
>  gstats1b = stats1b
> when (stats1c>stats1b) | (stats1c>stats1a) | (stats1c>stats1d)
>  gstats1c = stats1c
> when (stats1d>stats1b) | (stats1d>stats1c) | (stats1d>stats1a)
>  gstats1d = stats1d
>
> mstr = gstats1a + gstats1b + gstats1c + gstats1d
>
> I cant find where the error is...
>
> --
> Posted via http://www.ruby-forum.com/.
>

-- 
Kenichi Kamiya