[ruby-core:41562] Re: [ruby-trunk - Bug #5730][Open] Optinal block parameters assigns wrong

What would be the wantend behavior of this code:

	def show(element)
		proc { |a =3D 1, b =3D 2| [a, b] }.call(element)
	end

	a =3D 2
	show(a)

	b =3D [2]
	show(b)

Should the last line result in  [[2], 2] or in [2, 2]? Does that mean that =
code meant to handle any arbitrary objet will have to check for #to_ary fir=
st before handing  it anywhere and then by some magic heuristic decide whet=
her to wrap it in another array?

Konstantin

On Dec 9, 2011, at 00:59 , Yukihiro Matsumoto wrote:

>=20
> Issue #5730 has been reported by Yukihiro Matsumoto.
>=20
> ----------------------------------------
> Bug #5730: Optinal block parameters assigns wrong
> http://redmine.ruby-lang.org/issues/5730
>=20
> Author: Yukihiro Matsumoto
> Status: Open
> Priority: Normal
> Assignee:=20
> Category:=20
> Target version:=20
> ruby -v: ruby 2.0.0dev (2011-12-09 trunk 33990) [i486-linux]ruby 2.0.0dev=
 (2011-12-09 trunk 33990) [i486-linux]=20
>=20
>=20
> The following program do not expand the given array, but it should expand=
 the value.
>=20
>=20
> def foo(&block)
>  block.call([1,2])
> end
> h =3D foo{|k=3D6,v=3D8|
>  p [k,v]   # gives [[1,2],8] but should be [1,2]
> }
>=20
>=20
> --=20
> http://redmine.ruby-lang.org
>=20