Hello=2C

Thanks =2C but I only need 1 of the three category but whic= h one is chancing.

Roelof

>=3B Date: Sun=2C 14 Oct 2012 00:43:15 +0900
>=3B From: = rubytalk2dave@davearonson.com
>=3B Subject: Re: multiple array problem=
>=3B To: ruby-talk@ruby-lang.org
>=3B
>=3B On Sat=2C Oct 1= 3=2C 2012 at 7:35 AM=2C Roelof Wobben <=3Brwobben@hotmail.com>=3B wrote= :
>=3B
>=3B >=3B category1.article.each do |artikel|
>=3B= >=3B puts article.name
>=3B >=3B end
>=3B >=3B
>= =3B >=3B category2.article.each do |artikel|
>=3B >=3B puts articl= e.name
>=3B >=3B end
>=3B >=3B
>=3B >=3B category3.art= icle.each do |artikel|
>=3B >=3B puts article.name
>=3B >=3B = end
>=3B >=3B
>=3B >=3B But now I have 3 parts of code which = are almost the same.
>=3B >=3B Is there a way I can make 1 part of c= ode where the category is a variable.
>=3B
>=3B Sure. Make an a= rray out of your 3 arrays: [category1=2C category2=2C
>=3B category3].= Then call .each on THAT. E.g.:
>=3B
>=3B [category1=2C cate= gory2=2C category3].each do |category|
>=3B category.article.each = do |article|
>=3B puts article.name
>=3B end
>=3B = end
>=3B
>=3B Not sure where you're getting category.article f= rom though=3B is
>=3B category an instance of some class like Category= =2C that has an array
>=3B called article? (If so=2C I'd suggest maki= ng the name plural to show
>=3B it's a collection.)
>=3B
>= =3B Which reminds me=2C watch out for mismatches between human languages.>=3B What you originally wrote wouldn't work (at least not as intended)= =2C
>=3B since you're using "artikel" as your loop variable=2C and "ar= ticle"
>=3B inside it.
>=3B
>=3B -Dave
>=3B
>=3B= --
>=3B Dave Aronson=2C T. Rex of Codosaurus=2C LLC... aka
>=3B= Available Secret-Cleared Ruby/Rails Freelancer
>=3B (NoVa/DC/Remote)= =3B see http://www.Codosaur.us/.
>=3B