Re: multiple array problem

Hello=2C

Thanks =2C but I only need 1 of the three category but which one is chancin=
g.

Roelof


> Date: Sun=2C 14 Oct 2012 00:43:15 +0900
> From: [e-mail]
> Subject: Re: multiple array problem
> To: [e-mail]
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> On Sat=2C Oct 13=2C 2012 at 7:35 AM=2C Roelof Wobben <[e-mail]=
> wrote:
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> > category1.article.each do |artikel|
> >     puts article.name
> > end
> >
> > category2.article.each do |artikel|
> > puts article.name
> > end
> >
> > category3.article.each do |artikel|
> > puts article.name
> > end
> >
> > But now I have 3 parts of code which are almost the same.
> > Is there a way I can make 1 part of code where the category is a variab=
le.
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> Sure.  Make an array out of your 3 arrays: [category1=2C category2=2C
> category3].  Then call .each on THAT.  E.g.:
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>   [category1=2C category2=2C category3].each do |category|
>     category.article.each do |article|
>       puts article.name
>     end
>   end
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> Not sure where you're getting category.article from though=3B is
> category an instance of some class like Category=2C that has an array
> called article?  (If so=2C I'd suggest making the name plural to show
> it's a collection.)
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> Which reminds me=2C watch out for mismatches between human languages.
> What you originally wrote wouldn't work (at least not as intended)=2C
> since you're using "artikel" as your loop variable=2C and "article"
> inside it.
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> -Dave
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> --=20
> Dave Aronson=2C T. Rex of Codosaurus=2C LLC... aka
> Available Secret-Cleared Ruby/Rails Freelancer
> (NoVa/DC/Remote)=3B see http://www.Codosaur.us/.
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