From: Joel Pearson <lists@...>
Date: 2012-10-17T16:52:20+09:00
Subject: Re: Drop 1st and last particular character

Sagy Drucker wrote in post #1080132:
> You didn't mention what if you have three times '#'.
> e.g. input = "#1234#567#
> I assume you want output = "1234#567"
> Use the String function "sub" which substitute from the first occurrence
> only, on the input,
> Then reverse the input and use it again (to remove last occurrence)
> e.g.:
> myString.sub!('#','')
> myString.reverse!.sub!('#','').reverse!
> This will keep all the '#' chars in between.
>
> Sagy

No Sagy, that's not a good method:

"1#1234#567#1".sub!('#','').reverse!.sub!('#','').reverse!
=> "11234#5671"

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