From: "Jesús Gabriel y Galán" <jgabrielygalan@...>
Date: 2012-10-02T17:01:52+09:00
Subject: Re: how to read arrary with an array

On Tue, Oct 2, 2012 at 9:50 AM, Richard D. <lists@ruby-forum.com> wrote:
> Thanks for replies.  I at least understand it much better between the
> two posts and understand the code for the program.
>
> So confirm my basic understanding, basically in this case the each inner
> array would be a row, and each item would fall into some kind of column,
> to use a spread sheet reference.  So it would read
> col 1, col2
> row1 Getting, 1
> row2 Numbers, 9
> row3 Letters, 13.

Basically yes, just the indices start with 0. So an array with three
elements will have elements at 0, 1 and 2.

> Later the author just made the variables to reference just the columns;
> name: go to first column
> page:  go to second column.
>
> The author explained that an array is just a set of data.  He just
> didn't explain how an array within an array worked, but briefly showed
> it existed.

You just need to know that when you access a position of an array, it
returns whatever object sits there. It could be another array:

array_of_arrays = [ [1,2,3], [4,5,6]]

first_array = array_of_arrays[0] # get the object that sits at the
first position of the array

Now, first_array is another array, that behaves the same.

Jesus.