From: Joao Silva <lists@...>
Date: 2012-10-19T05:34:06+09:00
Subject: Truncate number which ends with 0 decimal

Hi All.

The question is how I can do to truncate a float number ending in 0.

I have an exercise where I truncate a float number to 2 decimals, the
problem is that if the decimal ends in 0 instead of return the full
number, only returns the first number.

For example:

 53454545.5459332345 >>> 53454545.54 is OK.

Now, this number:

 948484747.5000000 >>> 948484747.5 is incorrect because it should be
948484747.50

To truncate the number to 2 decimals I'm using this code:

###################################

 (number*100).to_i  / 100.0

##################################

which works correctly if the truncated decimal number does not end in 0.

Other examples:

#####################################################################

857474.555586767 ===> 857474.55 ==> is ok.
857474.50000000 ====> 857474.5 ==> is wrong >> Should be 857474.50

8120384.9876355 ===> 8120384.98 ==> is ok.
8120384.9000000 ===> 8120384.9 ==> is wrong >> Should be 8120384.90

#####################################################################

The question is whether there is some other way, that if the decimal
number ends in 0, not truncate the first issue, and I return the full
number.

Thanks.

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