[#399938] how to read arrary with an array — "Richard D." <lists@...>

Hello. I believe this is basic question, but I'm just starting to learn

19 messages 2012/10/02

[#400050] img src while sending email ruby cgi — Ferdous ara <lists@...>

Hi

16 messages 2012/10/05

[#400351] Drop 1st and last particular character — ajay paswan <lists@...>

What is the most efficient way to drop '#' from the first place and last

15 messages 2012/10/16

[#400374] database part of a desktop application — "Sebastjan H." <lists@...>

Hi,

14 messages 2012/10/16
[#400375] Re: database part of a desktop application — Chad Perrin <code@...> 2012/10/16

On Wed, Oct 17, 2012 at 05:28:39AM +0900, Sebastjan H. wrote:

[#400377] Re: database part of a desktop application — sto.mar@... 2012/10/17

Am 16.10.2012 23:24, schrieb Chad Perrin:

[#400389] Re: database part of a desktop application — Chad Perrin <code@...> 2012/10/17

On Wed, Oct 17, 2012 at 01:39:21PM +0900, sto.mar@web.de wrote:

[#400386] Unable to send attachment, and dealing with multiple attachment — ajay paswan <lists@...>

Hi,

11 messages 2012/10/17

[#400454] Hash with Integer key issue — Wayne Simmerson <lists@...>

Hi Im new to Ruby and am getting some unexpected results from a

18 messages 2012/10/19

[#400535] Name/symbol/object type clash? What is happening here? — Todd Benson <caduceass@...>

It's nonsense code, but I'm curious as to what is going on behind the scenes...

41 messages 2012/10/23

[#400556] Calling a method foo() or an object foo.method_call_here - both — Marc Heiler <lists@...>

Hello.

13 messages 2012/10/24

[#400650] OpenSSL ECDSA public key from private — Nokan Emiro <uzleepito@...>

Hi,

11 messages 2012/10/27

[#400680] Passing folder as argument ARGV? — Joz Private <lists@...>

Is there an easy way to pass multiple files on the command line?

15 messages 2012/10/28
[#400681] Re: Passing folder as argument ARGV? — brad smith <bradleydsmith@...> 2012/10/28

How are you traversing the directory you pass in on the command line ?

[#400697] File.readable? and /proc — Jeff Moore <lists@...>

root@nail:/projects/proc_fs# uname -a

13 messages 2012/10/28

[#400714] Marshal.load weird issue — "Pierre J." <lists@...>

Hi guys

12 messages 2012/10/28

[#400781] bug?: local variable created in if modifier not available in modified expression — "Mean L." <lists@...>

irb(main):001:0> local1 if local1 = "created"

21 messages 2012/10/30
[#400807] Re: bug?: local variable created in if modifier not available in modified expression — Bartosz Dziewoński <matma.rex@...> 2012/10/31

Oh, and in case it wasn't apparent: you can just add

[#400808] Re: bug?: local variable created in if modifier not available in modified expression — Eliezer Croitoru <eliezer@...> 2012/10/31

On 10/31/2012 4:52 PM, Bartosz Dziewoナгki wrote:

[#400809] Re: bug?: local variable created in if modifier not available in modified expression — Robert Klemme <shortcutter@...> 2012/10/31

On Wed, Oct 31, 2012 at 4:28 PM, Eliezer Croitoru <eliezer@ngtech.co.il>wrote:

[#400784] REXML & HTMLentities incorrectly map to UTF-8 — "Mark S." <lists@...>

I have some XML data (UTF 8) that I'm trying to convert into another XML

13 messages 2012/10/30

Calculation of heights

From: Joao Silva <lists@...>
Date: 2012-10-04 17:26:48 UTC
List: ruby-talk #400021
Hi All

The question I have is how to load a hash where the key is not numeric
or does not follow a cycle. I'm doing an exercise where I have to go
asking people's names and their corresponding heights, these the income
each in a different array, and then deposit them into a hash and get
over 2 meters, 1.60 meters minors, etc. The problem is how to charge the
hash data arrays. Here is the code:

##############################################################

heights=Hash.new
a=[]
b=[]
r=0
i=0

puts "calculation of heights"
while r!=2
  puts "enter name: "
  a[i]=gets.chomp.to_s
  puts "enter height: "
  b[i]=gets.chomp.to_f
  i=i+1
  puts "want to perform other income: 1-> yes, 2-> no: "
  r=gets.chomp.to_i
  puts ""
end

for i in 1..a.length
  for j in 1..b..length
    alturas[i]=a[i]
    alturas[j]=b[i]
  end
end

######################################################################

is not applicable in Ruby using for loops, but not the only language I
use then I get a little tricky to get used.

not if you understand the problem.

Thanks.

-- 
Posted via http://www.ruby-forum.com/.

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