From: Arlen Cuss <ar@...>
Date: 2012-10-29T10:25:39+09:00
Subject: Re: Newbie : Regular expression

Hi Muhammad,

That depends entirely on what the value of "r" is. The #{} is interpolation, like in strings.

e.g.

r = /boo/
regexp = Regexp.new("(^#{r}$)") 

regexp is now /(^(?-mix:boo)$)/, which is basically the same as saying /(^(?:boo)$)/, .. which is basically the same as /(^boo$)/ in this context.

In other words, the value of "r" gets included there, with any options on the regexp "r" set. If "r" is a String, its value is included verbatim, as if it was part of the regexp source.

Cheers,

Arlen 


On Monday, 29 October 2012 at 12:14 PM, Muhammad Salman wrote:

> Hi,
> 
> Can some one please tell me of an example expression which maps to this
> regex
> 
> "(^#{r}$)"
> 
> The ruby statement is
> 
> regex = Regexp.new("(^#{r}$)")
> 
> -- 
> Posted via http://www.ruby-forum.com/.