From: sto.mar@...
Date: 2012-10-18T08:08:48+09:00
Subject: Re: Drop 1st and last particular character

Am 17.10.2012 09:39, schrieb Sagy Drucker:
> You didn't mention what if you have three times '#'.
> e.g. input = "#1234#567#
> I assume you want output = "1234#567"
> Use the String function "sub" which substitute from the first occurrence only, on the input,
> Then reverse the input and use it again (to remove last occurrence)
> e.g.:
> myString.sub!('#','')
> myString.reverse!.sub!('#','').reverse!
> This will keep all the '#' chars in between.

this does not work if there is no '#'

1.9.3p194 :001 > myString = '123'
  => "123"
1.9.3p194 :0ß2 > myString.reverse!.sub!('#','').reverse!
NoMethodError: undefined method `reverse!' for nil:NilClass


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