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I'm apparently missing something fundamental in my knowledge of classes

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[#408712] Ruby web service with REST support — "Shubhada S." <lists@...>

Hi All,

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Hi community,

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I am trying to send an email using the code below. I am able to send the

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[#409031] tap { break } idiom deserves its own Kernel method? — Andy Lowry <lists@...>

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[#409072] Link To Masses Of External Data In Openoffice? — "Austin J." <lists@...>

This is what I want to do.

19 messages 2013/07/23
[#409102] Re: Link To Masses Of External Data In Openoffice? — Tamara Temple <tamouse.lists@...> 2013/07/24

[#409103] Re: Link To Masses Of External Data In Openoffice? — "Austin J." <lists@...> 2013/07/25

tamouse m. wrote in post #1116598:

[#409122] Re: Link To Masses Of External Data In Openoffice? — Tamara Temple <tamouse.lists@...> 2013/07/26

[#409142] Re: Link To Masses Of External Data In Openoffice? — "Austin J." <lists@...> 2013/07/26

tamouse m. wrote in post #1116750:

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Hello all,

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[#409195] Re: Working through Ch.10 for learning to program 2.0 (Chris Pine) — Harry Kakueki <list.push@...> 2013/07/29

I tried this and came up with a one-liner that seems to do it. It sorts the

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I am new to Ruby & Watir, and I am having a nightmare with IE and Script

11 messages 2013/07/31

Re: how to create structure like bellow

From: Tamara Temple <tamouse.lists@...>
Date: 2013-07-23 21:30:18 UTC
List: ruby-talk #409066
On Jul 23, 2013, at 2:40 PM, Expert Alart <lists@ruby-forum.com> wrote:

> Hi...
>=20
> I need a structure like bellow

"Bellow" is to shout like an elephant.

"Below" means comes after.

> , i know its not correct syntax, but just
> trying to give an idea so that i can get a correct answer ..
>=20
> row value :
>=20
> a-z15a6=3D5
> b-z15a6=3D4
> a-z15a7=3D3
> b-z15a7=3D3
> ......
> .......
> a-z16af=3D3
>=20
>=20
>=20
>=20
>=20
> I need to store Value in this...
> z15a=3D{[a-z15a6=3D>5,b-z15a6=3D>4],[a-z15a7=3D>3,b-z15a7=3D>3],....n}
> z16a=3D{[a-z16af=3D>3,b-z16af=3D>4],[a-z16ag=3D>3,b-z16ag=3D>3],.......n=
}
>=20
>=20
> possible like this
>=20
>=20
> =
[z15a=3D>{[a-z15a6=3D>5,b-z15a6=3D>4],[a-z15a7=3D>3,b-z15a7=3D>3],....n}},=
z16a=3D>{[a-z16af=3D>3,b-z16af=3D>4],[a-z16ag=3D>3,b-z16ag=3D>3],.......n}=
]
>=20
>=20
> then i need to calculate value from this example
> total of z15a  =3D 5+4+3+3  (top row)
> Total of z16a  =3D 3+ 4 +3 +3 (bottom row)
>=20
> but dont understand whats the logic will i use ...
>=20
> Can any one please give me some light
>=20
> Thanks
>=20
> --=20
> Posted via http://www.ruby-forum.com/.
>=20

Where is the data coming from? A file? A spreadsheet? A database? This =
information will aid greatly in giving you a possible answer. What you =
have above is rather complicated, and it seems you would make your life =
a lot simpler if you made it less complex.

For example, you say your desired outcome is the sum of the values of =
each hash element in each row. I'm think there must be a much easier way =
to organize this rather than drilling through the above data structure. =
Please show where the information comes from; maybe it's simpler than =
you're thinking.



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