On Wed, Jul 10, 2013 at 7:14 AM, <sto.mar@web.de> wrot= e:

Am 10.07.2013 00:03, schrieb stefan heinrich:

can u say how I have to use the Hash with the headers. I have tried
everything but it doesn't work.

That's not a very useful information...

You can take my first example:

Am 09.07.2013 17:47, schrieb sto.mar@web.de:

array =3D ['Car', 'Dog', 'Dog', 'Car', '= ;Dog']
indices =3D Hash.new {|h,k| h[k] =3D [] }
array.each_with_index {|element, index| indices[element] << index } indices
=A0 =A0# =3D> {"Car"=3D>[0, 3], "Dog"=3D>[1, 2= , 4]}
indices['Car']
=A0 =A0# =3D> [0, 3]
indices['Dog']
=A0 =A0# =3D> [1, 2, 4]

assuming your data is given as a 2-dimensional array:

data =3D [
=A0 ['Dog', 12],
=A0 ['Car', 14],
=A0 ['Car', 67],
=A0 ['Dog', 98],
=A0 ['Dog', 32]
]

then this would work (first, I create a hash with [] as the
default value, that's the trickiest part of the whole thing):

values =3D Hash.new {|h,k| h[k] =3D [] }
data.each {|header, value| values[header] << value }

You can also use Enumerable#group_by:

irb(main):008:0> data.group_by {|s,i| s}

=3D> = {"Dog"=3D>[["Dog", 12], ["Dog", 98], [&quo= t;Dog", 32]], "Car"=3D>[["Car", 14], ["Car= ", 67]]}

irb(main):009:0> data.group_by {|s,i| s}.each {|k,v| v.m= ap! {|s,i| i}}

=3D> {"Dog"=3D>[12, 98, 32], "= ;Car"=3D>[14, 67]}

=A0

Depending on how your data is given, you need to modify
the second line.

I was going to ask in = what structure the data is available. =A0That bit of information seems to b= e missing from the discussion.

I suggest you also look into the docs for the Hash class and
make heavy use of irb.

That's excellent advice.

<= div class=3D"gmail_extra">Kind regards

robert

-- remember.guy do |as, often| as.you_can - without end
http://blog.rubybestpractices.com/

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