Re: Iteration anomalu

Hi,

In second iteration the value we are getting in 'i' is [0..3]

Certainly it will print all the value of a and then it prints the new line... it works properly.

try this.....

  for i in [0..a.length] do
    print i
    print a[i], "\n"
  end
  
  123456789

print a[0..2]

if you want the same result, try this it will print new line

for i in 0...a.length do
   print a[i], "\n"
end

123
456
789


Cheers, Dhanabal




On Thursday 18 July 2013 02:13 AM, Andrew D. wrote:
> Surely this is a FAQ but I can't figure out how I would search for an
> explanation for this behavior. In short, this code
>
>    a = [[1,2,3], [4,5,6], [7,8,9]]
>
>    for x in a do
>      print x, "\n"
>    end
>
>    for i in [0..a.length] do
>      print a[i], "\n"
>    end
>
> yields this result:
>
>
> 123
> 456
> 789
> 123456789
>
> Why does the second iteration evaluate all the prints before printing
> the newline?
>
> I have some puzzling variations on this too, but I am sure that the
> answer to this will clear them up. Thanks!
>
> FWIW, the reason I even consider the second iteration style, old-school
> that it is, is because I want to do a double-nested iteration through a,
> in this way:
>
>    for i in [0..a.length] do
>      for j in [i+1..a.length] do
>        # etc... processing lower-left-hand triangle of possibilities...
>