From: Stefano Crocco Date: 2013-07-16T22:56:57+09:00 Subject: Re: Get part of matrix On Tuesday 16 July 2013 Diego N. wrote > Hi! > I'm looking for a way to get part of matix: eg: > my matrix: > [10, 11, 12, 13, 14, 15, 16, 17, 18, 19] > [20, 21, 22, 23, 24, 25, 26, 27, 28, 29] > [30, 31, 32, 33, 34, 35, 36, 37, 38, 39] > [40, 41, 42, 43, 44, 45, 46, 47, 48, 49] > [50, 51, 52, 53, 54, 55, 56, 57, 58, 59] > [60, 61, 62, 63, 64, 65, 66, 67, 68, 69] > [70, 71, 72, 73, 74, 75, 76, 77, 78, 79] > [80, 81, 82, 83, 84, 85, 86, 87, 88, 89] > [90, 91, 92, 93, 94, 95, 96, 97, 98, 99] > > How could i get part ( square ) of the matrix? If i choose the number > 54, i would like to get the numbers [43,44,45,53,55,63,64,65], a 3x3 > square. > > I'm trying to understand the doc ( > http://ruby-doc.org/stdlib-1.9.3/libdoc/matrix/rdoc/Matrix.html ). > > There's a method to get this? > > thanks, > Dieog > > -- > Posted via http://www.ruby-forum.com/. I think the method you want is Matrix#minor. If I understand correctly, you want a 3x3 matrix "centered" on the element 54, corresponding to row 4 and column 4. You can do: matrix.minor(3..5,3..5) or matrix.minor(3,3,3,3) In the first case, you pass the range of rows and columns to return as two Range objects; in the second case, you give the first row and the number of rows, the starting column and the number of columns. I hope this helps Stefano