From: Heesob Park <phasis@...>
Date: 2009-03-27T10:14:52+09:00
Subject: [ruby-core:23030] Re: [Bug #1317] Creating a range with strings

2009/3/27 Michael Selig <redmine@ruby-lang.org>:
> Issue #1317 has been updated by Michael Selig.
>
>
> This is a (possibly confusing) consequence of the behaviour of String#next.
> For most sortable objects, the following is true:
>
> obj.next > obj
>
> but not for strings. For example:
>
> "9".next => "10"
> but
> "10" > "9" => false
>
> So if you think of a range as a potential "for" loop in a C-style syntax it would be:
>
> for (obj = start; obj < end; obj = next(obj)) ....
>
> then you will see that the loop will stop immediately when start is "2" and end is "10".
>
> Obviously the behaviour of string comparison can't be changed.
>
I'm not sure the range use String#next.

On ruby 1.9.1 and 1.8.6, "Z".next is "AA".

But the result is different from each other.

[sidns@ns httpd]$ ruby -v -e "p(('A'..'z').to_a)"
ruby 1.8.6 (2007-09-24 patchlevel 111) [i686-linux]
["A", "B", "C", "D", "E", "F", "G", "H", "I", "J", "K", "L", "M", "N",
"O", "P", "Q", "R", "S", "T", "U", "V", "W", "X", "Y", "Z"]

[siweb@localhost ~]$ ruby -v -e "p(('A'..'z').to_a)"
ruby 1.9.1p0 (2009-01-30 revision 21907) [i686-linux]
["A", "B", "C", "D", "E", "F", "G", "H", "I", "J", "K", "L", "M", "N",
"O", "P", "Q", "R", "S", "T", "U", "V", "W", "X", "Y", "Z", "[", "\\",
"]", "^", "_", "`", "a", "b", "c", "d", "e", "f", "g", "h", "i", "j",
"k", "l", "m", "n", "o", "p", "q", "r", "s", "t", "u", "v", "w", "x",
"y", "z"]


Regards,

Park Heesob