From: Robert Klemme <shortcutter@...>
Date: 2012-08-10T05:13:33+09:00
Subject: Re: Time-efficient program

On Thu, Aug 9, 2012 at 5:52 PM, ajay paswan <lists@ruby-forum.com> wrote:
> Suppose you are given a program, now you are given a task to minimize
> the time, what will be your approach?

What time?

> and how will you measure the time needed?
> I think if we can get total clock cycle by any mean, that could be the
> best measure. If so, how can I get that?

If you want to measure execution time of a Ruby program there's Benchmark.

irb19robert@fussel:~$ irb19 -r benchmark
irb(main):001:0> Benchmark.measure { sleep 1 }
=>   0.000000   0.000000   0.000000 (  1.000137)

irb(main):002:0> Benchmark.measure { 10_000.times { |i| 10 + i } }
=>   0.000000   0.000000   0.000000 (  0.001673)

irb(main):003:0> Benchmark.measure { 1000_000.times { |i| 10 + i } }
=>   0.170000   0.000000   0.170000 (  0.170213)

irb(main):004:0> Benchmark.bm {|x| x.report("foo") { sleep 1 }}
       user     system      total        real
foo  0.000000   0.000000   0.000000 (  1.000152)
=> [  0.000000   0.000000   0.000000 (  1.000152)
]

http://rubydoc.info/stdlib/benchmark/frames

Kind regards

robert


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