\d+\.\d+)\s+\).+$\s+(\d+\.\d+)\s+(\d+\.\d+)\s+(\d+\.\d+)\s+(\d+\.\d+= )\s+(\d+\.\d+)\s+(\d+\.\d+)\s+$$ But that's a long ugly regex that repeats the {capture+whitespace} = element (\d+\.\d+)\s+ three times, then six times=20 Is there a Ruby regex way to simplify/clarify the regex so that it = explicitly shows that the capture+whitespace is repeated three times = then six ? thanks, Peter --Apple-Mail=_33790B76-BF72-44F6-AAB4-0D7A08E0C3AD Content-Transfer-Encoding: quoted-printable Content-Type: text/html; charset=us-ascii Hello,

I = have some data that I would like to parse with a regex. The raw data = looks like so:

9.028: = I:4551 ( 0.095 0.096 0.136 ) T:4551 ( 0.095 = 0.096 0.098 0.117 0.136 0.136 = )

14.066: = I:4601 ( 0.095 0.096 5.344 ) T:9152 ( 0.095 = 0.096 0.098 0.119 4.352 5.344 = )

19.099: = I:4609 ( 0.094 0.096 0.132 ) T:13761 ( 0.094 = 0.096 0.098 0.123 4.352 5.344 = )

24.033: = I:4528 ( 0.093 0.095 0.130 ) T:18289 ( 0.094 = 0.096 0.098 0.124 3.344 5.344 = )

I= can extract the data that I want with the following:

^(\d+\.\d+): = I:\d+\s+$\s+(\d+\.\d+)\s+(\d+\.\d+)\s+(\d+\.\d+)\s+$.+$\s+(\d+\.\d+)\s+= (\d+\.\d+)\s+(\d+\.\d+)\s+(\d+\.\d+)\s+(\d+\.\d+)\s+(\d+\.\d+)\s+$$

I can even = name the fields with the longer:

^(?<offset_secs>\d+\.\d+): = I:\d+\s+$\s+(?<median_stall>\d+\.\d+)\s+(?<p90_stall>\d+\.\d+= )\s+(?<max_stall>\d+\.\d+)\s+$.+$\s+(\d+\.\d+)\s+(\d+\.\d+)\s+(\d+= \.\d+)\s+(\d+\.\d+)\s+(\d+\.\d+)\s+(\d+\.\d+)\s+$$

But that's a long ugly = regex that repeats the {capture+whitespace} element (\d+\.\d+)\s+ three times, then six = times

Is there a Ruby regex way to simplify/clarify the regex = so that it explicitly shows that the capture+whitespace is repeated = three times then six ?

thanks,

Peter

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