From: "nobu (Nobuyoshi Nakada)" <nobu@...>
Date: 2013-07-26T12:55:52+09:00
Subject: [ruby-core:56192] [ruby-trunk - Bug #8692][Rejected] segv in fiddle


Issue #8692 has been updated by nobu (Nobuyoshi Nakada).

Status changed from Open to Rejected

=begin
(({time()})) returns (({time_t})), not pointer.
As Fiddle doesn't provide (({TYPE_TIME_T})) currently, you have to use (({TYPE_LONG})) instead.

  require 'fiddle'
  libc = Fiddle.dlopen(nil)
  time = Fiddle::Function.new(libc['time'], [Fiddle::TYPE_VOIDP], Fiddle::TYPE_LONG)
  puts time.call(nil)
=end

----------------------------------------
Bug #8692: segv in fiddle
https://bugs.ruby-lang.org/issues/8692#change-40681

Author: zzak (Zachary Scott)
Status: Rejected
Priority: Normal
Assignee: 
Category: ext
Target version: 
ruby -v: ruby 2.1.0dev (2013-07-26 trunk 42177) [x86_64-darwin12.4.0]
Backport: 1.9.3: UNKNOWN, 2.0.0: UNKNOWN


=begin
  require 'fiddle'
  libc = Fiddle.dlopen('libc.dylib')
  time = Fiddle::Function.new( libc['time'], [Fiddle::TYPE_VOIDP], Fiddle::TYPE_VOIDP )
  puts time.call(nil)

stack trace: ((<URL:https://gist.github.com/zzak/6085700>))
=end



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