[ruby-core:103045] [Ruby master Misc#17751] Do these instructions (<<, +, [0..n]) modify the original string without creating copies?

Issue #17751 has been updated by stiuna (Juan Gregorio).


But use this:
``` ruby
data = [header, str]
data[1] << "some data"
```


Or this:
``` ruby
data = {:header => "", :str => ""}
data[:str] << "some data"
```


Isn't this slower than just using a string directly?
``` ruby
str << "some data"
```


Besides then I have to concatenate and to do that in an array or a hash copies must be created.

----------------------------------------
Misc #17751: Do these instructions (<<,+,[0..n]) modify the original string without creating copies?
https://bugs.ruby-lang.org/issues/17751#change-91106

* Author: stiuna (Juan Gregorio)
* Status: Open
* Priority: Normal
----------------------------------------
In my program a string increases considerably in size inside a loop, at the end of that loop a header is created that will have to go to the beginning of that string.

During the whole loop:

``` ruby
str << "some data"
```


At the end:

``` ruby
header = "other data"
str = header + str
```

I understand that using (+) creates a copy to then modify the original variable, that is not desirable, I would like to do something similar to (<<), which I understand does not create copies.

If I do this:
``` ruby
header << str
```

I would have two variables with a very large size.

I also have this other code and I don't know if it is an "in place" modifier:
``` ruby
str = "12345"
str[0..2] = ""
#s => 45
```


In short, I want to know what instructions I should use to remove a given range from a string and how to concatenate to both the beginning and end of the target string without having to create copies.



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