From: cart4for1@... Date: 2021-03-26T22:34:40+00:00 Subject: [ruby-core:103045] [Ruby master Misc#17751] Do these instructions (<<, +, [0..n]) modify the original string without creating copies? Issue #17751 has been updated by stiuna (Juan Gregorio). But use this: ``` ruby data = [header, str] data[1] << "some data" ``` Or this: ``` ruby data = {:header => "", :str => ""} data[:str] << "some data" ``` Isn't this slower than just using a string directly? ``` ruby str << "some data" ``` Besides then I have to concatenate and to do that in an array or a hash copies must be created. ---------------------------------------- Misc #17751: Do these instructions (<<,+,[0..n]) modify the original string without creating copies? https://bugs.ruby-lang.org/issues/17751#change-91106 * Author: stiuna (Juan Gregorio) * Status: Open * Priority: Normal ---------------------------------------- In my program a string increases considerably in size inside a loop, at the end of that loop a header is created that will have to go to the beginning of that string. During the whole loop: ``` ruby str << "some data" ``` At the end: ``` ruby header = "other data" str = header + str ``` I understand that using (+) creates a copy to then modify the original variable, that is not desirable, I would like to do something similar to (<<), which I understand does not create copies. If I do this: ``` ruby header << str ``` I would have two variables with a very large size. I also have this other code and I don't know if it is an "in place" modifier: ``` ruby str = "12345" str[0..2] = "" #s => 45 ``` In short, I want to know what instructions I should use to remove a given range from a string and how to concatenate to both the beginning and end of the target string without having to create copies. -- https://bugs.ruby-lang.org/ Unsubscribe: