[ruby-list:44155] Re: 2個づつの組を作る方法のすべて

On 10/28/07, [e-mail] <[e-mail]> wrote:
>
>  [1,2,3,4] => [[[1,2],[3,4]],[1,3][2,4],[1,4],[2,3]]]
>

ハリーです。
前に私の出したコードをちょっと調整したら、

require 'enumerator'
arr = [1,2,3,4]
f,arr_sub = arr[0..1], arr[2..-1]

(arr.length-1).times do |y|
  gr = []
  gr << f
  arr_sub.each_slice(2) {|x| gr << x}
  p gr
  f[1], arr_sub[y] = arr_sub[y], f[1]
end



#[[1, 2], [3, 4]]
#[[1, 3], [2, 4]]
#[[1, 4], [2, 3]]

Harry

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