[ruby-core:69540] [Ruby trunk - Feature #10769] Negative counterpart to Enumerable#slice_when

Issue #10769 has been updated by Yukihiro Matsumoto.


#chunk_while looks good to me.  Go ahead.

Matz.


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Feature #10769: Negative counterpart to Enumerable#slice_when
https://bugs.ruby-lang.org/issues/10769#change-52867

* Author: Tsuyoshi Sawada
* Status: Open
* Priority: Normal
* Assignee: 
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It seems to me that most useful cases of `Enumerable#slice_when` involve a negative condition inside the block. That observation seems to be confirmed by  the official examples in http://docs.ruby-lang.org/ja/2.2.0/method/Enumerable/i/slice_when.html. In these examples, the conditions inside the block are negations of what would is intended (which is expressed in the comment above each code).

    # 1ずつ増加する部分配列ごとに分ける。
    [1,2,4,9,10,11,12,15,16,19,20,21]
    .slice_when{|i, j| i + 1 != j}.to_a    # => [[1, 2], [4], [9, 10, 11, 12], [15, 16], [19, 20, 21]]

    # ソート済の配列を近い値(差が6以内)の部分配列ごとに分ける。
    [3, 11, 14, 25, 28, 29, 29, 41, 55, 57]
    .slice_when{|i, j| 6 < j - i}.to_a    # => [[3], [11, 14], [25, 28, 29, 29], [41], [55, 57]]

    # 増加のみの部分配列ごとに分ける。
    [0, 9, 2, 2, 3, 2, 7, 5, 9, 5]
    .slice_when{|i, j| i > j}.to_a    # => [[0, 9], [2, 2, 3], [2, 7], [5, 9], [5]]

    # 隣り合う偶数同士、奇数同士の部分配列ごとに分ける。
    [7, 5, 9, 2, 0, 7, 9, 4, 2, 0]
    .slice_when{|i, j| i.even? != j.even?}.to_a    # => [[7, 5, 9], [2, 0], [7, 9], [4, 2, 0]]

I propose that there should be a method on `Enumerable` that works like `slice_when` except that it works with the block negatively as compared to `slice_when`. Let us call this method `Enumerable#chunk_while`. Then, the examples above would be written more naturally without having a negative notion in the blocks.

    # 1ずつ増加する部分配列ごとに分ける。
    [1,2,4,9,10,11,12,15,16,19,20,21]
    .chunk_while{|i, j| i + 1 == j}.to_a

    # ソート済の配列を近い値(差が6以内)の部分配列ごとに分ける。
    [3, 11, 14, 25, 28, 29, 29, 41, 55, 57]
    .chunk_while{|i, j| j - i <= 6}.to_a

    # 増加のみの部分配列ごとに分ける。
    [0, 9, 2, 2, 3, 2, 7, 5, 9, 5]
    .chunk_while{|i, j| i <= j}.to_a

    # 隣り合う偶数同士、奇数同士の部分配列ごとに分ける。
    [7, 5, 9, 2, 0, 7, 9, 4, 2, 0]
    .chunk_while{|i, j| i.even? == j.even?}.to_a

I am not sure about the method name. There can be a better name.



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