From: "alexeymuranov (Alexey Muranov)" <redmine@...>
Date: 2013-09-20T21:35:22+09:00
Subject: [ruby-core:57290] [ruby-trunk - Feature #8895] Destructuring	Assignment for Hash


Issue #8895 has been updated by alexeymuranov (Alexey Muranov).


=begin
How about this:

  (x, y, *rest, :a => a, :b => b, **options) = 1, 2, 3, 4, :a => :foo, :b => :bar, :c => false, :d => true
  x       # => 1
  y       # => 2
  rest    # => [3, 4]
  a       # => :foo
  b       # => :bar
  options # => {:c=>false, :d=>true}
=end

----------------------------------------
Feature #8895: Destructuring Assignment for Hash
https://bugs.ruby-lang.org/issues/8895#change-41905

Author: chendo (Jack Chen)
Status: Open
Priority: Normal
Assignee: 
Category: 
Target version: 


=begin
Given Ruby already supports destructuring assignment with Array (a, b = [1, 2]), I propose destructuring assignments for Hash.

== Basic example

  params = {name: "John Smith", age: 42}
  {name: name, age: age} = params

  # name == "John Smith"
  # age == 42

This would replace a common pattern of assigning hash values to local variables to work with.

== General syntax

  { <key-expr> => <variable_name>, ��� } = <object that responds to #[]>

  # Symbols
  { foo: bar } = { foo: "bar" }
  bar == "bar"

  # Potential shorthand
  { foo } = { foo: "bar" }
  foo == "bar"

== Use cases:

  # MatchData
  { username: username, age: age } = "user:jsmith age:42".match(/user:(?<username>\w+) age:(?<age>\d+)/)
  username == "jsmith"
  age == "42"

== Edge cases

  # Variable being assigned to more than once should use the last one
  { foo: var, bar: var } = {foo: 1, bar: 2}
  var == 2

Thoughts?
=end



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